What is the answer to 3^{34+2x}=27^{4x+2} ?

The answer to 3^{34+2x}=27^{4x+2} is x= 14/5

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3^{34+2x}=27^{4x+2}

3^{34 + 2 x} = 2 7^{4 x + 2}

x = \frac{14}{5}

Decimal Notation

x = 2.8

Solution steps

3^{34 + 2 x} = 2 7^{4 x + 2}

Apply exponent rules

34 + 2 x = 3 (4 x + 2)

Solve

34 + 2 x = 3 (4 x + 2) : x = \frac{14}{5}

x = \frac{14}{5}

2^{r} - (1 + \frac{r}{100})^{72} = 0

\frac{2}{3 - 2 ^{x}} = 5

2 e^{2 x} = e^{x + 1}

a, f (a + 2) = 2^{(a + 2)}

5^{x + 1} + 6 \cdot 5^{x} = 6

What is the answer to 3^{34+2x}=27^{4x+2} ?
The answer to 3^{34+2x}=27^{4x+2} is x= 14/5
Solve for x: 3^{34+2x}=27^{4x+2}
The solution is x= 14/5