What is the answer to 4^{8^{3+2x}}=2^{2^{7x-1}} ?

The answer to 4^{8^{3+2x}}=2^{2^{7x-1}} is x=11

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4^{8^{3+2x}}=2^{2^{7x-1}}

4^{8^{3 + 2 x}} = 2^{2^{7 x - 1}}

x = 11

Solution steps

4^{8^{3 + 2 x}} = 2^{2^{7 x - 1}}

Apply exponent rules

1 + 3 (3 + 2 x) = 7 x - 1

Solve

1 + 3 (3 + 2 x) = 7 x - 1 : x = 11

x = 11

2 \cdot 3^{\frac{x}{5}} = 1

9^{x + 2} = 8 1^{3 x - 1}

3^{a} - 3^{a - 2} = 6^{3}

7^{3 x + 4} = 28

9^{5} = 3^{x + 2}

What is the answer to 4^{8^{3+2x}}=2^{2^{7x-1}} ?
The answer to 4^{8^{3+2x}}=2^{2^{7x-1}} is x=11
Solve for x: 4^{8^{3+2x}}=2^{2^{7x-1}}
The solution is x=11