What is the answer to 4^{2x}=8^{2x-1} ?

The answer to 4^{2x}=8^{2x-1} is x= 3/2

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4^{2x}=8^{2x-1}

4^{2 x} = 8^{2 x - 1}

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

4^{2 x} = 8^{2 x - 1}

Apply exponent rules

4 x = 3 (2 x - 1)

Solve

4 x = 3 (2 x - 1) : x = \frac{3}{2}

x = \frac{3}{2}

(\frac{1}{3})^{3 x} = 2 7^{x - 1}

6^{x + 2} = 21

18 = 5 e^{x + 3}

2^{2 x} + 2 (2^{x}) - 15 = 0

2 5^{x^{2}} \cdot 5^{5 x} = 125