What is the answer to 7^{2x+1}-49^x=42 ?

The answer to 7^{2x+1}-49^x=42 is x= 1/2

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7^{2x+1}-49^x=42

7^{2 x + 1} - 4 9^{x} = 42

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

7^{2 x + 1} - 4 9^{x} = 42

Apply exponent rules

2 x = 1

Solve

2 x = 1 : x = \frac{1}{2}

x = \frac{1}{2}

9^{x} = 2 \cdot 3^{x} + 3

3 \cdot 2^{x - 1} - 1 = 2

1 3^{- 7 x} - 8 = 85

e^{x} = 2 e^{\frac{x}{2}} + 15

e^{- 10} = \frac{1}{e ^{x}}

What is the answer to 7^{2x+1}-49^x=42 ?
The answer to 7^{2x+1}-49^x=42 is x= 1/2
Solve for x: 7^{2x+1}-49^x=42
The solution is x= 1/2