What is the answer to 2^{2x}-20(2^x)+64=0 ?

The answer to 2^{2x}-20(2^x)+64=0 is x=4,x=2

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2^{2x}-20(2^x)+64=0

2^{2 x} - 20 (2^{x}) + 64 = 0

x = 4, x = 2

Solution steps

2^{2 x} - 20 (2^{x}) + 64 = 0

Apply exponent rules

(2^{x})^{2} - 20 \cdot 2^{x} + 64 = 0

Rewrite the equation with

2^{x} = u

(u)^{2} - 20 u + 64 = 0

Solve

u^{2} - 20 u + 64 = 0 : u = 16, u = 4

u = 16, u = 4

Substitute back

u = 2^{x},

solve for

x

Solve

2^{x} = 16 : x = 4

Solve

2^{x} = 4 : x = 2

x = 4, x = 2

2 = e^{9 x}

e^{2 x} - 2 e^{- 2 x} = 1

e^{x} - 8 = 51

m, x^{\frac{1}{m}} = 4

3.7 5^{r} = 2.76

What is the answer to 2^{2x}-20(2^x)+64=0 ?
The answer to 2^{2x}-20(2^x)+64=0 is x=4,x=2
Solve for x: 2^{2x}-20(2^x)+64=0
The solution is x=4,x=2