What is the answer to 4^x*3^{5x}+3=21 ?

The answer to 4^x*3^{5x}+3=21 is x=(ln(18))/(ln(972))

Solve for x: 4^x*3^{5x}+3=21

The solution is x=(ln(18))/(ln(972))

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4^{x} \cdot 3^{5 x} + 3 = 21

x = \frac{ln ( 18 )}{ln ( 972 )}

Decimal Notation

x = 0.42015 \dots

Solution steps

4^{x} \cdot 3^{5 x} + 3 = 21

Apply exponent rules

(lo g_{3} (4) x + 5 x) ln (3) = ln (18)

Solve

(lo g_{3} (4) x + 5 x) ln (3) = ln (18) : x = \frac{ln ( 18 )}{ln ( 972 )}

x = \frac{ln ( 18 )}{ln ( 972 )}

6^{x^{2} - 3} = 3 6^{x}

x, 5^{x} = t

2^{2 x + 1} + 2^{x} = 3

x, e^{x y} y = 0

x, 5^{x} = 3

What is the answer to 4^x*3^{5x}+3=21 ?
The answer to 4^x*3^{5x}+3=21 is x=(ln(18))/(ln(972))
Solve for x: 4^x*3^{5x}+3=21
The solution is x=(ln(18))/(ln(972))