What is the answer to 7^{5x-4}=21 ?

The answer to 7^{5x-4}=21 is x=(ln(21)+4ln(7))/(5ln(7))

Solve for x: 7^{5x-4}=21

The solution is x=(ln(21)+4ln(7))/(5ln(7))

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7^{5 x - 4} = 21

x = \frac{ln ( 21 ) + 4 ln ( 7 )}{5 ln ( 7 )}

Decimal Notation

x = 1.11291 \dots

Solution steps

7^{5 x - 4} = 21

Apply exponent rules

(5 x - 4) ln (7) = ln (21)

Solve

(5 x - 4) ln (7) = ln (21) : x = \frac{ln ( 21 ) + 4 ln ( 7 )}{5 ln ( 7 )}

x = \frac{ln ( 21 ) + 4 ln ( 7 )}{5 ln ( 7 )}

t = e^{λ (t - 1)}

c, 1 = e^{e (0) + c}

2 e^{x} = 5 e^{x} + 12

t, 5^{t} = 7

12 5^{3 x - 4} = 2 5^{4 x + 2}

What is the answer to 7^{5x-4}=21 ?
The answer to 7^{5x-4}=21 is x=(ln(21)+4ln(7))/(5ln(7))
Solve for x: 7^{5x-4}=21
The solution is x=(ln(21)+4ln(7))/(5ln(7))