What is the answer to ((1000000)/(2^d))=1950 ?

The answer to ((1000000)/(2^d))=1950 is d=-(ln(39/20000))/(ln(2))

Solve for d: ((1000000)/(2^d))=1950

The solution is d=-(ln(39/20000))/(ln(2))

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(\frac{1000000}{2 ^{d}}) = 1950

d = - \frac{ln ( \frac{39}{20000} )}{ln ( 2 )}

Decimal Notation

d = 9.00231 \dots

Solution steps

(\frac{1000000}{2 ^{d}}) = 1950

Apply exponent rules

- d ln (2) = ln (\frac{39}{20000})

Solve

- d ln (2) = ln (\frac{39}{20000}) : d = - \frac{ln ( \frac{39}{20000} )}{ln ( 2 )}

d = - \frac{ln ( \frac{39}{20000} )}{ln ( 2 )}

Verify Solutions:

d = - \frac{ln ( \frac{39}{20000} )}{ln ( 2 )}

True

The solution is

d = - \frac{ln ( \frac{39}{20000} )}{ln ( 2 )}

578962 = 3 e^{0.03183 (x)}

2^{6 x + 12} = 3 2^{2 x + 4}

40 = 2^{x}

5^{3 x + 1} = 6^{2 x + 1}

1^{x} = 1.2

What is the answer to ((1000000)/(2^d))=1950 ?
The answer to ((1000000)/(2^d))=1950 is d=-(ln(39/20000))/(ln(2))
Solve for d: ((1000000)/(2^d))=1950
The solution is d=-(ln(39/20000))/(ln(2))