What is the answer to 5^{3x+1}=6^{2x+1} ?

The answer to 5^{3x+1}=6^{2x+1} is x=(ln(6)-ln(5))/(3ln(5)-2ln(6))

Solve for x: 5^{3x+1}=6^{2x+1}

The solution is x=(ln(6)-ln(5))/(3ln(5)-2ln(6))

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5^{3 x + 1} = 6^{2 x + 1}

x = \frac{ln ( 6 ) - ln ( 5 )}{3 ln ( 5 ) - 2 ln ( 6 )}

Decimal Notation

x = 0.14646 \dots

Solution steps

5^{3 x + 1} = 6^{2 x + 1}

Apply exponent rules

(3 x + 1) ln (5) = (2 x + 1) ln (6)

Solve

(3 x + 1) ln (5) = (2 x + 1) ln (6) : x = \frac{ln ( 6 ) - ln ( 5 )}{3 ln ( 5 ) - 2 ln ( 6 )}

x = \frac{ln ( 6 ) - ln ( 5 )}{3 ln ( 5 ) - 2 ln ( 6 )}

1^{x} = 1.2

e^{a^{5}} = 2.4

2 e^{a^{8}} - 8 = 64

5^{x} \cdot 5^{x + 4} = 25

2 = e^{0.1 x}

What is the answer to 5^{3x+1}=6^{2x+1} ?
The answer to 5^{3x+1}=6^{2x+1} is x=(ln(6)-ln(5))/(3ln(5)-2ln(6))
Solve for x: 5^{3x+1}=6^{2x+1}
The solution is x=(ln(6)-ln(5))/(3ln(5)-2ln(6))