What is the answer to 7^{x+3}=5 ?

The answer to 7^{x+3}=5 is x=(ln(5))/(ln(7))-3

Solve for x: 7^{x+3}=5

The solution is x=(ln(5))/(ln(7))-3

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7^{x + 3} = 5

x = \frac{ln ( 5 )}{ln ( 7 )} - 3

Decimal Notation

x = - 2.17291 \dots

Solution steps

7^{x + 3} = 5

Apply exponent rules

(x + 3) ln (7) = ln (5)

Solve

(x + 3) ln (7) = ln (5) : x = \frac{ln ( 5 )}{ln ( 7 )} - 3

x = \frac{ln ( 5 )}{ln ( 7 )} - 3

7^{x + 3} = 1

1^{x} = 0.1

3^{x + 9} = 5^{3 x}

2^{x + 2} = \frac{1}{16}

0 = e^{2 x} + 1

What is the answer to 7^{x+3}=5 ?
The answer to 7^{x+3}=5 is x=(ln(5))/(ln(7))-3
Solve for x: 7^{x+3}=5
The solution is x=(ln(5))/(ln(7))-3