What is the answer to \sqrt[3]{25^2}=5^p ?

The answer to \sqrt[3]{25^2}=5^p is p= 4/3

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\sqrt[3]{25^2}=5^p

p = \frac{4}{3}

Decimal Notation

p = 1.33333 \dots

Solution steps

Apply exponent rules

\frac{4}{3} = p

Switch sides

p = \frac{4}{3}

(\frac{1}{3})^{x + 2} = 3 x + 1

1 5^{4 x} = 8^{x - 9}

3^{2 n - 1} = \frac{1}{81}

3^{x + 1} + 3^{x + 2} + 3^{x - 1} = 999

t, y = e^{3 t}

What is the answer to \sqrt[3]{25^2}=5^p ?
The answer to \sqrt[3]{25^2}=5^p is p= 4/3
Solve for p: \sqrt[3]{25^2}=5^p
The solution is p= 4/3