What is the answer to solvefor p,2^p-15=q^2 ?

The answer to solvefor p,2^p-15=q^2 is p=(ln(q^2+15))/(ln(2))

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solvefor p,2^p-15=q^2

solve for

p, 2^{p} - 15 = q^{2}

p = \frac{ln ( q ^{2} + 15 )}{ln ( 2 )}

Solution steps

2^{p} - 15 = q^{2}

Move

15

to the right side

2^{p} = q^{2} + 15

Apply exponent rules

p ln (2) = ln (q^{2} + 15)

Solve

p ln (2) = ln (q^{2} + 15) : p = \frac{ln ( q ^{2} + 15 )}{ln ( 2 )}

p = \frac{ln ( q ^{2} + 15 )}{ln ( 2 )}

2^{3 n + 1} = 64

- 2 = 4^{x}

100 = 2 e^{0.5 t}

2^{24 x + 12} = 1 6^{6 x + 3}

3 - e^{x - 1} = 1

What is the answer to solvefor p,2^p-15=q^2 ?
The answer to solvefor p,2^p-15=q^2 is p=(ln(q^2+15))/(ln(2))