What is the answer to 3^{2x-1}=0.05 ?

The answer to 3^{2x-1}=0.05 is x=(ln(0.15))/(2ln(3))

Solve for x: 3^{2x-1}=0.05

The solution is x=(ln(0.15))/(2ln(3))

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3^{2 x - 1} = 0.05

x = \frac{ln ( 0.15 )}{2 ln ( 3 )}

Decimal Notation

x = - 0.86341 \dots

Solution steps

3^{2 x - 1} = 0.05

Apply exponent rules

(2 x - 1) ln (3) = ln (0.05)

Solve

(2 x - 1) ln (3) = ln (0.05) : x = \frac{ln ( 0.15 )}{2 ln ( 3 )}

x = \frac{ln ( 0.15 )}{2 ln ( 3 )}

3^{2 x - 1} = 0.07

2 \cdot 1 0^{x} = 66

3^{x} \cdot 27 = \frac{1}{9}

3^{2 x - 2} + 3 x - 1 = 12

2^{x} 3^{x} = 81

What is the answer to 3^{2x-1}=0.05 ?
The answer to 3^{2x-1}=0.05 is x=(ln(0.15))/(2ln(3))
Solve for x: 3^{2x-1}=0.05
The solution is x=(ln(0.15))/(2ln(3))