What is the answer to 0=4-3^x ?

The answer to 0=4-3^x is x=(2ln(2))/(ln(3))

The solution is x=(2ln(2))/(ln(3))

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0=4-3^x

0 = 4 - 3^{x}

x = \frac{2 ln ( 2 )}{ln ( 3 )}

Decimal Notation

x = 1.26185 \dots

Solution steps

0 = 4 - 3^{x}

Add

3^{x}

to both sides

0 + 3^{x} = 4 - 3^{x} + 3^{x}

Simplify

3^{x} = 4

Apply exponent rules

x ln (3) = ln (4)

Solve

x ln (3) = ln (4) : x = \frac{2 ln ( 2 )}{ln ( 3 )}

x = \frac{2 ln ( 2 )}{ln ( 3 )}

3 e^{x} = e^{3 x}

x, 2 e^{3 x} - 10 y = 6

3 7^{x} = 12

5^{x} = 35

1 6^{- x} = 4^{x + 8}