What is the answer to 2*5^x=4^x ?

The answer to 2*5^x=4^x is x=-(ln(2))/(ln(5)-2ln(2))

Solve for x: 2*5^x=4^x

The solution is x=-(ln(2))/(ln(5)-2ln(2))

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2 \cdot 5^{x} = 4^{x}

x = - \frac{ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

Decimal Notation

x = - 3.10628 \dots

Solution steps

2 \cdot 5^{x} = 4^{x}

Apply exponent rules

ln (2) + x ln (5) = x ln (4)

Solve

ln (2) + x ln (5) = x ln (4) : x = - \frac{ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

x = - \frac{ln ( 2 )}{ln ( 5 ) - 2 ln ( 2 )}

(5)^{k} = 0.2

x = 1 - e^{- 2 x}

8 e^{\frac{x}{4}} = 1

4 9^{3 - 2 z} = \frac{1}{7}

3 2^{x} = 2^{2 x + 1}

What is the answer to 2*5^x=4^x ?
The answer to 2*5^x=4^x is x=-(ln(2))/(ln(5)-2ln(2))
Solve for x: 2*5^x=4^x
The solution is x=-(ln(2))/(ln(5)-2ln(2))