What is the answer to (3^{27})^{x+3}=(27^9)^{x+3} ?

The answer to (3^{27})^{x+3}=(27^9)^{x+3} is True for all x

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(3^{27})^{x+3}=(27^9)^{x+3}

(3^{27})^{x + 3} = (2 7^{9})^{x + 3}

True for all x

Solution steps

(3^{27})^{x + 3} = (2 7^{9})^{x + 3}

Apply exponent rules

27 (x + 3) = 27 (x + 3)

Both sides are equal

True for all x

k \frac{2}{3 ^{k}} = 1 0^{- 8}

9^{x} - 1 = 9

e^{4 x} = 8

e^{4 x} = 4

2^{x^{2} - 9} = 1

What is the answer to (3^{27})^{x+3}=(27^9)^{x+3} ?
The answer to (3^{27})^{x+3}=(27^9)^{x+3} is True for all x
Solve for x: (3^{27})^{x+3}=(27^9)^{x+3}
The solution is True for all x