What is the answer to 3^{n+4}=27^{2n} ?

The answer to 3^{n+4}=27^{2n} is n= 4/5

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3^{n+4}=27^{2n}

3^{n + 4} = 2 7^{2 n}

n = \frac{4}{5}

Decimal Notation

n = 0.8

Solution steps

3^{n + 4} = 2 7^{2 n}

Apply exponent rules

n + 4 = 6 n

Solve

n + 4 = 6 n : n = \frac{4}{5}

n = \frac{4}{5}

6.6 = 320 (0.5)^{\frac{x}{7}}

2^{x^{2 - 2}} = 4 x

9^{x - 1} = 5^{2 x - 2}

y = \frac{x}{e ^{x}}, x

e^{x - 3} = 2^{x - 1}