What is the answer to 2(3)^x=34,log_{10}(x) ?

The answer to 2(3)^x=34,log_{10}(x) is x=(ln(17))/(ln(3))

Solve for x: 2(3)^x=34,log_{10}(x)

The solution is x=(ln(17))/(ln(3))

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2 (3)^{x} = 34, lo g_{10} (x)

x = \frac{ln ( 17 )}{ln ( 3 )}

Decimal Notation

x = 2.57890 \dots

Solution steps

2 (3)^{x} = 34

Divide both sides by

2

3^{x} = 17

Apply exponent rules

x ln (3) = ln (17)

Solve

x ln (3) = ln (17) : x = \frac{ln ( 17 )}{ln ( 3 )}

x = \frac{ln ( 17 )}{ln ( 3 )}

9 x 2 7^{x} = 27

a = 27.2 e^{0.031 t}

79 \cdot 1 0^{5 x} = 78

2^{2 x} - 3 \cdot 2^{x} = 4

e^{0.5 x} = 0.5

What is the answer to 2(3)^x=34,log_{10}(x) ?
The answer to 2(3)^x=34,log_{10}(x) is x=(ln(17))/(ln(3))
Solve for x: 2(3)^x=34,log_{10}(x)
The solution is x=(ln(17))/(ln(3))