What is the answer to (343^3)^{5+2x}=(7^{3x})^2 ?

The answer to (343^3)^{5+2x}=(7^{3x})^2 is x=-15/4

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(343^3)^{5+2x}=(7^{3x})^2

(34 3^{3})^{5 + 2 x} = (7^{3 x})^{2}

x = - \frac{15}{4}

Decimal Notation

x = - 3.75

Solution steps

(34 3^{3})^{5 + 2 x} = (7^{3 x})^{2}

Apply exponent rules

9 (5 + 2 x) = 6 x

Solve

9 (5 + 2 x) = 6 x : x = - \frac{15}{4}

x = - \frac{15}{4}

e^{2 x - 6} = 44.7

n = 2^{\frac{n}{8}}

208 (1.04)^{t} = 279 (1.01)^{t}

15 = A (1 - e^{- k^{2}})

36 = 18 (1 6^{0.0125 x})

What is the answer to (343^3)^{5+2x}=(7^{3x})^2 ?
The answer to (343^3)^{5+2x}=(7^{3x})^2 is x=-15/4
Solve for x: (343^3)^{5+2x}=(7^{3x})^2
The solution is x=-15/4