What is the answer to 3^{2x+5}=(1/27)^{x-4} ?

The answer to 3^{2x+5}=(1/27)^{x-4} is x= 7/5

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3^{2x+5}=(1/27)^{x-4}

3^{2 x + 5} = (\frac{1}{27})^{x - 4}

x = \frac{7}{5}

Decimal Notation

x = 1.4

Solution steps

3^{2 x + 5} = (\frac{1}{27})^{x - 4}

Apply exponent rules

2 x + 5 = - 3 (x - 4)

Solve

2 x + 5 = - 3 (x - 4) : x = \frac{7}{5}

x = \frac{7}{5}

e^{x} x^{2} + 4 x e^{x} + 3 e^{x} = 0

2^{x} - 15 = 17

e^{11 x + 1} = k

9^{x - 2} = 3

25 e^{- 0.3 x} = 12

What is the answer to 3^{2x+5}=(1/27)^{x-4} ?
The answer to 3^{2x+5}=(1/27)^{x-4} is x= 7/5
Solve for x: 3^{2x+5}=(1/27)^{x-4}
The solution is x= 7/5