What is the answer to solvefor x,ln(y)=e^x+ln(2) ?

The answer to solvefor x,ln(y)=e^x+ln(2) is x=ln(ln(y)-ln(2))

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solvefor x,ln(y)=e^x+ln(2)

solve for

x, ln (y) = e^{x} + ln (2)

x = ln (ln (y) - ln (2))

Solution steps

ln (y) = e^{x} + ln (2)

Switch sides

e^{x} + ln (2) = ln (y)

Move

ln (2)

to the right side

e^{x} = ln (y) - ln (2)

Apply exponent rules

x = ln (ln (y) - ln (2))

u, y = x^{u}

9^{- x - 4} = 27

30 = 80 e^{(- x) (1)}

3^{n + 1} = 2^{n}

[(- \frac{2}{3})^{2}]^{x} = 1

What is the answer to solvefor x,ln(y)=e^x+ln(2) ?
The answer to solvefor x,ln(y)=e^x+ln(2) is x=ln(ln(y)-ln(2))