What is the answer to x^22^x-2^x7=0 ?

The answer to x^22^x-2^x7=0 is x=-sqrt(7),x=sqrt(7)

Solve for x: x^22^x-2^x7=0

The solution is x=-sqrt(7),x=sqrt(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} 2^{x} - 2^{x} 7 = 0

x = - 7, x = 7

Decimal Notation

x = - 2.64575 \dots, x = 2.64575 \dots

Solution steps

x^{2} \cdot 2^{x} - 2^{x} \cdot 7 = 0

Factor

2^{x} (x + 7) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2^{x} = 0 or x + 7 = 0 or x - 7 = 0

Solve

2^{x} = 0 :

No Solution for

x \in R

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

x = - 7, x = 7

5^{3 - 2 x} = 4 (7^{x})

e^{x} x^{2} = 0

lo g_{5} (5^{x}) = 2

x, 2^{x} + 3^{y} = 11

8^{2} + 8^{2} = 4^{x}

What is the answer to x^22^x-2^x7=0 ?
The answer to x^22^x-2^x7=0 is x=-sqrt(7),x=sqrt(7)
Solve for x: x^22^x-2^x7=0
The solution is x=-sqrt(7),x=sqrt(7)