What is the answer to 10(3^x)+1=5 ?

The answer to 10(3^x)+1=5 is x=(ln(2/5))/(ln(3))

Solve for x: 10(3^x)+1=5

The solution is x=(ln(2/5))/(ln(3))

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10 (3^{x}) + 1 = 5

x = \frac{ln ( \frac{2}{5} )}{ln ( 3 )}

Decimal Notation

x = - 0.83404 \dots

Solution steps

10 (3^{x}) + 1 = 5

Move

1

to the right side

10 \cdot 3^{x} = 4

Divide both sides by

10

3^{x} = \frac{2}{5}

Apply exponent rules

x ln (3) = ln (\frac{2}{5})

Solve

x ln (3) = ln (\frac{2}{5}) : x = \frac{ln ( \frac{2}{5} )}{ln ( 3 )}

x = \frac{ln ( \frac{2}{5} )}{ln ( 3 )}

2 \cdot 7^{r - 4} = 7

2^{2 + x} + 2^{2 - x} = 17

28 = (100 - 20) 0. 5^{x} + 20

x, 5^{y} = 2^{x} + 1

9 - 3 x = (\frac{1}{27})^{x + 3}

What is the answer to 10(3^x)+1=5 ?
The answer to 10(3^x)+1=5 is x=(ln(2/5))/(ln(3))
Solve for x: 10(3^x)+1=5
The solution is x=(ln(2/5))/(ln(3))