What is the answer to 7^x= 1/(\sqrt[3]{7)} ?

The answer to 7^x= 1/(\sqrt[3]{7)} is x=-1/3

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7^x= 1/(\sqrt[3]{7)}

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

Apply exponent rules

x = - \frac{1}{3}

2 z^{(2 - 7 z)} = 0

8 \cdot 3^{4 x} = 1

73 = 2 7^{x}

7^{3^{x}} = \frac{1}{49}

What is the answer to 7^x= 1/(\sqrt[3]{7)} ?
The answer to 7^x= 1/(\sqrt[3]{7)} is x=-1/3
Solve for x: 7^x= 1/(\sqrt[3]{7)}
The solution is x=-1/3