What is the answer to 10^{4x-2}=2^{4x+7} ?

The answer to 10^{4x-2}=2^{4x+7} is x=(7ln(2)+2ln(10))/(4ln(5))

Solve for x: 10^{4x-2}=2^{4x+7}

The solution is x=(7ln(2)+2ln(10))/(4ln(5))

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1 0^{4 x - 2} = 2^{4 x + 7}

x = \frac{7 ln ( 2 ) + 2 ln ( 10 )}{4 ln ( 5 )}

Decimal Notation

x = 1.46902 \dots

Solution steps

1 0^{4 x - 2} = 2^{4 x + 7}

Apply exponent rules

(4 x - 2) ln (10) = (4 x + 7) ln (2)

Solve

(4 x - 2) ln (10) = (4 x + 7) ln (2) : x = \frac{7 ln ( 2 ) + 2 ln ( 10 )}{4 ln ( 5 )}

x = \frac{7 ln ( 2 ) + 2 ln ( 10 )}{4 ln ( 5 )}

4^{2 x + 3} = 8^{x - 2}

x, 0.5 = 2^{x}

0.34 3^{- x + 1} = 0.34 3^{x + 3}

x, e^{- x} - x = 0

What is the answer to 10^{4x-2}=2^{4x+7} ?
The answer to 10^{4x-2}=2^{4x+7} is x=(7ln(2)+2ln(10))/(4ln(5))
Solve for x: 10^{4x-2}=2^{4x+7}
The solution is x=(7ln(2)+2ln(10))/(4ln(5))