What is the answer to (sqrt(x))^{-1+log_{2}(x)}=2 ?

The answer to (sqrt(x))^{-1+log_{2}(x)}=2 is x=4,x= 1/2

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(sqrt(x))^{-1+log_{2}(x)}=2

(x)^{- 1 + l o g_{2} (x)} = 2

x = 4, x = \frac{1}{2}

Decimal Notation

x = 4, x = 0.5

Solution steps

(x)^{- 1 + l o g_{2} (x)} = 2

Apply exponent rules

(- 1 + lo g_{2} (x)) ln (x) = ln (2)

Solve

(- 1 + lo g_{2} (x)) ln (x) = ln (2) : x = 4, x = \frac{1}{2}

x = 4, x = \frac{1}{2}

Verify Solutions:

x = 4

True

, x = \frac{1}{2}

True

The solutions are

x = 4, x = \frac{1}{2}

55 = 5 + c e^{(\frac{l n ( 50 )}{c})}

3^{1 + 2 x} = 27

e^{- 0.2 t} = 0

4^{1 - 7 x} = 5^{x}

1600 = 800 (1.0227)^{t}

What is the answer to (sqrt(x))^{-1+log_{2}(x)}=2 ?
The answer to (sqrt(x))^{-1+log_{2}(x)}=2 is x=4,x= 1/2
Solve for x: (sqrt(x))^{-1+log_{2}(x)}=2
The solution is x=4,x= 1/2