What is the answer to 10^{2^x}=5 ?

The answer to 10^{2^x}=5 is x=(ln(\frac{ln(5))/(ln(10)))}{ln(2)}

Solve for x: 10^{2^x}=5

The solution is x=(ln(\frac{ln(5))/(ln(10)))}{ln(2)}

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1 0^{2^{x}} = 5

x = \frac{ln ( \frac{l n ( 5 )}{l n ( 10 )} )}{ln ( 2 )}

Decimal Notation

x = - 0.51669 \dots

Solution steps

1 0^{2^{x}} = 5

Apply exponent rules

x ln (2) = ln (\frac{ln ( 5 )}{ln ( 10 )})

Solve

x ln (2) = ln (\frac{ln ( 5 )}{ln ( 10 )}) : x = \frac{ln ( \frac{l n ( 5 )}{l n ( 10 )} )}{ln ( 2 )}

x = \frac{ln ( \frac{l n ( 5 )}{l n ( 10 )} )}{ln ( 2 )}

1200 = 6 \cdot 3^{t}

1 0^{\frac{x}{4}} = 8

\frac{k ^{x + 3}}{k ^{3 x}} = k^{x}

e^{9 - 4 x} = 6

2 7^{3 x} = 9^{x + 1}

What is the answer to 10^{2^x}=5 ?
The answer to 10^{2^x}=5 is x=(ln(\frac{ln(5))/(ln(10)))}{ln(2)}
Solve for x: 10^{2^x}=5
The solution is x=(ln(\frac{ln(5))/(ln(10)))}{ln(2)}