What is the answer to 2^{-x+2}=6^{2x-3} ?

The answer to 2^{-x+2}=6^{2x-3} is x=(ln(864))/(ln(72))

Solve for x: 2^{-x+2}=6^{2x-3}

The solution is x=(ln(864))/(ln(72))

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2^{- x + 2} = 6^{2 x - 3}

x = \frac{ln ( 864 )}{ln ( 72 )}

Decimal Notation

x = 1.58103 \dots

Solution steps

2^{- x + 2} = 6^{2 x - 3}

Apply exponent rules

(- x + 2) ln (2) = (2 x - 3) ln (6)

Solve

(- x + 2) ln (2) = (2 x - 3) ln (6) : x = \frac{ln ( 864 )}{ln ( 72 )}

x = \frac{ln ( 864 )}{ln ( 72 )}

x, 2^{x - 2 y} = 4

2^{2 x} = 2^{x + 1}

3^{x + 4} = 2^{1 - 3 x}

24 = 3 (4)^{- 5 x + 1}

x^{2} 2^{x} - 2 x = 0

What is the answer to 2^{-x+2}=6^{2x-3} ?
The answer to 2^{-x+2}=6^{2x-3} is x=(ln(864))/(ln(72))
Solve for x: 2^{-x+2}=6^{2x-3}
The solution is x=(ln(864))/(ln(72))