What is the answer to 5=17^{t-2} ?

The answer to 5=17^{t-2} is t=(ln(5))/(ln(17))+2

Solve for t: 5=17^{t-2}

The solution is t=(ln(5))/(ln(17))+2

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5 = 1 7^{t - 2}

t = \frac{ln ( 5 )}{ln ( 17 )} + 2

Decimal Notation

t = 2.56806 \dots

Solution steps

5 = 1 7^{t - 2}

Apply exponent rules

ln (5) = (t - 2) ln (17)

Solve

ln (5) = (t - 2) ln (17) : t = \frac{ln ( 5 )}{ln ( 17 )} + 2

t = \frac{ln ( 5 )}{ln ( 17 )} + 2

2 = 4^{x}

64 = 8^{x - 2}

4^{(x - 3)} = 5

- 3 e^{- 3 x} + 1 = 0

3 2^{x + 1} = 64

What is the answer to 5=17^{t-2} ?
The answer to 5=17^{t-2} is t=(ln(5))/(ln(17))+2
Solve for t: 5=17^{t-2}
The solution is t=(ln(5))/(ln(17))+2