What are the solutions to the equation 9x^2+24x+16=0 ?

The solutions to the equation 9x^2+24x+16=0 are x=-4/3

Find the zeros of 9x^2+24x+16=0

The zeros of 9x^2+24x+16=0 are x=-4/3

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9 x^{2} + 24 x + 16 = 0

x = - \frac{4}{3}

Solution steps

9 x^{2} + 24 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 \cdot 16}{2 \cdot 9}

2 4^{2} - 4 \cdot 9 \cdot 16 = 0

x_{1, 2} = \frac{- 24 \pm 0}{2 \cdot 9}

x = \frac{- 24}{2 \cdot 9}

\frac{- 24}{2 \cdot 9} = - \frac{4}{3}

x = - \frac{4}{3}

The solution to the quadratic equation is:

x = - \frac{4}{3}

z^{2} + 5 z - 24

\frac{k}{- 3} + 3 = - 2

8 x + 2 (- 4 x - 5) = 7

x + 3 = - 2

(\frac{3}{2})^{- 1}

What are the solutions to the equation 9x^2+24x+16=0 ?
The solutions to the equation 9x^2+24x+16=0 are x=-4/3
Find the zeros of 9x^2+24x+16=0
The zeros of 9x^2+24x+16=0 are x=-4/3