What is the answer to 68.6=41.8e^{k(2029-2005)} ?

The answer to 68.6=41.8e^{k(2029-2005)} is k=(ln(343/209))/(24)

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68.6=41.8e^{k(2029-2005)}

68.6 = 41.8 e^{k (2029 - 2005)}

k = \frac{ln ( \frac{343}{209} )}{24}

Decimal Notation

k = 0.02064 \dots

Solution steps

68.6 = 41.8 e^{k (2029 - 2005)}

Switch sides

41.8 e^{k (2029 - 2005)} = 68.6

Multiply both sides by

10

418 e^{k (2029 - 2005)} = 686

Divide both sides by

418

e^{k (2029 - 2005)} = \frac{343}{209}

Apply exponent rules

k (2029 - 2005) = ln (\frac{343}{209})

Solve

k (2029 - 2005) = ln (\frac{343}{209}) : k = \frac{ln ( \frac{343}{209} )}{24}

k = \frac{ln ( \frac{343}{209} )}{24}

4^{3 x} = 128

x, x + 3 y = 5 e^{2 x + y}

- e^{1 - x} x + e^{1 - x} = 0

2 \cdot 3^{x} + 3^{x} = 81

(\frac{1}{3})^{5 x} = 243

What is the answer to 68.6=41.8e^{k(2029-2005)} ?
The answer to 68.6=41.8e^{k(2029-2005)} is k=(ln(343/209))/(24)