What is the answer to 8^{-4x}=13^{x+4} ?

The answer to 8^{-4x}=13^{x+4} is x=(4ln(13))/(-12ln(2)-ln(13))

Solve for x: 8^{-4x}=13^{x+4}

The solution is x=(4ln(13))/(-12ln(2)-ln(13))

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8^{- 4 x} = 1 3^{x + 4}

x = \frac{4 ln ( 13 )}{- 12 ln ( 2 ) - ln ( 13 )}

Decimal Notation

x = - 0.94276 \dots

Solution steps

8^{- 4 x} = 1 3^{x + 4}

Apply exponent rules

- 4 x ln (8) = (x + 4) ln (13)

Solve

- 4 x ln (8) = (x + 4) ln (13) : x = \frac{4 ln ( 13 )}{- 12 ln ( 2 ) - ln ( 13 )}

x = \frac{4 ln ( 13 )}{- 12 ln ( 2 ) - ln ( 13 )}

5^{2 x} - 2 (5^{x}) = 15

9^{x} = e^{x + 9}

8^{x - 1} = 1

0.85 = A_{0} e^{k \cdot 600}

80 = 100 - 30 \cdot e^{- 0.04 t}

What is the answer to 8^{-4x}=13^{x+4} ?
The answer to 8^{-4x}=13^{x+4} is x=(4ln(13))/(-12ln(2)-ln(13))
Solve for x: 8^{-4x}=13^{x+4}
The solution is x=(4ln(13))/(-12ln(2)-ln(13))