What is the answer to 79=31^x ?

The answer to 79=31^x is x=(ln(79))/(ln(31))

The solution is x=(ln(79))/(ln(31))

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79=31^x

79 = 3 1^{x}

x = \frac{ln ( 79 )}{ln ( 31 )}

Decimal Notation

x = 1.27241 \dots

Solution steps

79 = 3 1^{x}

Apply exponent rules

ln (79) = x ln (31)

Solve

ln (79) = x ln (31) : x = \frac{ln ( 79 )}{ln ( 31 )}

x = \frac{ln ( 79 )}{ln ( 31 )}

9^{x} = e^{x + 2}

2^{2 x + 15} = 3^{x - 40}

7^{y} = 14

95 = 3 5^{x}

2^{5 x - 1} = 3^{x}