What is the answer to 2^x=(4^{x-2})/8 ?

The answer to 2^x=(4^{x-2})/8 is x=7

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2^x=(4^{x-2})/8

2^{x} = \frac{4 ^{x - 2}}{8}

x = 7

Solution steps

2^{x} = \frac{4 ^{x - 2}}{8}

Multiply both sides by

8

2^{x} \cdot 8 = \frac{4 ^{x - 2}}{8} \cdot 8

Simplify

2^{x} \cdot 8 = 4^{x - 2}

Apply exponent rules

x + 3 = 2 (x - 2)

Solve

x + 3 = 2 (x - 2) : x = 7

x = 7

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