What is the answer to 2^{x-8}=5 ?

The answer to 2^{x-8}=5 is x=(ln(5))/(ln(2))+8

Solve for x: 2^{x-8}=5

The solution is x=(ln(5))/(ln(2))+8

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2^{x - 8} = 5

x = \frac{ln ( 5 )}{ln ( 2 )} + 8

Decimal Notation

x = 10.32192 \dots

Solution steps

2^{x - 8} = 5

Apply exponent rules

(x - 8) ln (2) = ln (5)

Solve

(x - 8) ln (2) = ln (5) : x = \frac{ln ( 5 )}{ln ( 2 )} + 8

x = \frac{ln ( 5 )}{ln ( 2 )} + 8

8^{x^{2} - 4} = 1

- 2 \cdot 5^{x + 2} + 2 5^{x + 1} = 375

x, 2^{x - 9} = 9

2^{x^{2} + 1} = 4^{x}

6^{x - 1} - 2 = 62

What is the answer to 2^{x-8}=5 ?
The answer to 2^{x-8}=5 is x=(ln(5))/(ln(2))+8
Solve for x: 2^{x-8}=5
The solution is x=(ln(5))/(ln(2))+8