What are the solutions to the equation x^3-5x^2-4x+20=0 ?

The solutions to the equation x^3-5x^2-4x+20=0 are x=5,x=-2,x=2

Find the zeros of x^3-5x^2-4x+20=0

The zeros of x^3-5x^2-4x+20=0 are x=5,x=-2,x=2

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x^{3} - 5 x^{2} - 4 x + 20 = 0

x = 5, x = - 2, x = 2

Solution steps

x^{3} - 5 x^{2} - 4 x + 20 = 0

Factor

x^{3} - 5 x^{2} - 4 x + 20 : (x - 5) (x + 2) (x - 2)

(x - 5) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 2 = 0 or x - 2 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = 5, x = - 2, x = 2

z^{4} = - 1

n^{3} = 16

4 x^{4} - 18 x^{2} = 0

x^{3} + 30 = 3

x^{3} + 2 x^{2} + x = 0

What are the solutions to the equation x^3-5x^2-4x+20=0 ?
The solutions to the equation x^3-5x^2-4x+20=0 are x=5,x=-2,x=2
Find the zeros of x^3-5x^2-4x+20=0
The zeros of x^3-5x^2-4x+20=0 are x=5,x=-2,x=2