What are the solutions to the equation 20=[5+(0.12x)/(10)]^{20} ?

The solutions to the equation 20=[5+(0.12x)/(10)]^{20} are x=-319.86780…,x=-513.46552…

Find the zeros of 20=[5+(0.12x)/(10)]^{20}

The zeros of 20=[5+(0.12x)/(10)]^{20} are x=-319.86780…,x=-513.46552…

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20 = [5 + \frac{0.12 x}{10}]^{20}

x = - 319.86780 \dots, x = - 513.46552 \dots

Solution steps

20 = [5 + \frac{0.12 x}{10}]^{20}

Switch sides

[5 + \frac{0.12 x}{10}]^{20} = 20

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = - 319.86780 \dots, x = - 513.46552 \dots

x^{4} - 4 x^{2} = 0

x^{4} - 3 x^{2} + 1 = 0

x^{3} = 729

x^{4} - 11 x^{2} + 10 = 0

x^{3} - 6 x^{2} + 3 x + 10 = 0

What are the solutions to the equation 20=[5+(0.12x)/(10)]^{20} ?
The solutions to the equation 20=[5+(0.12x)/(10)]^{20} are x=-319.86780…,x=-513.46552…
Find the zeros of 20=[5+(0.12x)/(10)]^{20}
The zeros of 20=[5+(0.12x)/(10)]^{20} are x=-319.86780…,x=-513.46552…