What are the solutions to the equation 9x^4-24x^3+16x^2=0 ?

The solutions to the equation 9x^4-24x^3+16x^2=0 are x=0,x= 4/3

Find the zeros of 9x^4-24x^3+16x^2=0

The zeros of 9x^4-24x^3+16x^2=0 are x=0,x= 4/3

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9 x^{4} - 24 x^{3} + 16 x^{2} = 0

x = 0, x = \frac{4}{3}

Solution steps

9 x^{4} - 24 x^{3} + 16 x^{2} = 0

Factor

9 x^{4} - 24 x^{3} + 16 x^{2} : x^{2} (3 x - 4)^{2}

x^{2} (3 x - 4)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x - 4 = 0

Solve

3 x - 4 = 0 : x = \frac{4}{3}

The solutions are

x = 0, x = \frac{4}{3}

x^{6} - 26 x^{3} - 27 = 0

x^{3} - 5 x^{2} + 2 x + 8 = 0

x^{4} - 2 x^{2} = 2 x^{2}

4 (x^{4} + 1) = 5 x^{2}

x^{3} = x^{2}

What are the solutions to the equation 9x^4-24x^3+16x^2=0 ?
The solutions to the equation 9x^4-24x^3+16x^2=0 are x=0,x= 4/3
Find the zeros of 9x^4-24x^3+16x^2=0
The zeros of 9x^4-24x^3+16x^2=0 are x=0,x= 4/3