What are the solutions to the equation x^3+2x^2+3x+6=0 ?

The solutions to the equation x^3+2x^2+3x+6=0 are x=-2,x=sqrt(3)i,x=-sqrt(3)i

Find the zeros of x^3+2x^2+3x+6=0

The zeros of x^3+2x^2+3x+6=0 are x=-2,x=sqrt(3)i,x=-sqrt(3)i

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x^{3} + 2 x^{2} + 3 x + 6 = 0

x = - 2, x = 3 i, x = - 3 i

Solution steps

x^{3} + 2 x^{2} + 3 x + 6 = 0

Factor

x^{3} + 2 x^{2} + 3 x + 6 : (x + 2) (x^{2} + 3)

(x + 2) (x^{2} + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 3 = 0 : x = 3 i, x = - 3 i

The solutions are

x = - 2, x = 3 i, x = - 3 i

x^{4} - 10 x^{2} + 29 = 8

x, x^{3} + y^{3} = 1

m^{3} = 64

4.7 x 1 0^{1} = 4.7 x^{10}

x^{3} + 6 x^{2} + 9 x = 0

What are the solutions to the equation x^3+2x^2+3x+6=0 ?
The solutions to the equation x^3+2x^2+3x+6=0 are x=-2,x=sqrt(3)i,x=-sqrt(3)i
Find the zeros of x^3+2x^2+3x+6=0
The zeros of x^3+2x^2+3x+6=0 are x=-2,x=sqrt(3)i,x=-sqrt(3)i