What are the solutions to the equation -x^3+6x^2-9x+4=0 ?

The solutions to the equation -x^3+6x^2-9x+4=0 are x=1,x=4

Find the zeros of -x^3+6x^2-9x+4=0

The zeros of -x^3+6x^2-9x+4=0 are x=1,x=4

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- x^{3} + 6 x^{2} - 9 x + 4 = 0

x = 1, x = 4

Solution steps

- x^{3} + 6 x^{2} - 9 x + 4 = 0

Factor

- x^{3} + 6 x^{2} - 9 x + 4 : - (x - 1)^{2} (x - 4)

- (x - 1)^{2} (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x - 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 4 = 0 : x = 4

The solutions are

x = 1, x = 4

x^{4} - 37 x^{2} + 36 = 0

x^{3} - 7 x + 12 = 0

y, y^{3} = x

x^{4} - 13 x^{2} + 37 = 7

x^{3} + x^{2} - 6 x = 0

What are the solutions to the equation -x^3+6x^2-9x+4=0 ?
The solutions to the equation -x^3+6x^2-9x+4=0 are x=1,x=4
Find the zeros of -x^3+6x^2-9x+4=0
The zeros of -x^3+6x^2-9x+4=0 are x=1,x=4