What are the solutions to the equation 4x^4-37x^2+9=0 ?

The solutions to the equation 4x^4-37x^2+9=0 are x=3,x=-3,x= 1/2 ,x=-1/2

Find the zeros of 4x^4-37x^2+9=0

The zeros of 4x^4-37x^2+9=0 are x=3,x=-3,x= 1/2 ,x=-1/2

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4 x^{4} - 37 x^{2} + 9 = 0

x = 3, x = - 3, x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 3, x = - 3, x = 0.5, x = - 0.5

Solution steps

4 x^{4} - 37 x^{2} + 9 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

4 u^{2} - 37 u + 9 = 0

Solve

4 u^{2} - 37 u + 9 = 0 : u = 9, u = \frac{1}{4}

u = 9, u = \frac{1}{4}

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 9 : x = 3, x = - 3

Solve

x^{2} = \frac{1}{4} : x = \frac{1}{2}, x = - \frac{1}{2}

The solutions are

x = 3, x = - 3, x = \frac{1}{2}, x = - \frac{1}{2}

27 x^{3} - 343 = 0

(2 x - 5) (3 x^{2} + 7 x - 6) = 0

- x^{3} + 4 x^{2} - 5 x + 2 = 0

54 = a^{4}

(7^{2})^{4} = n^{8}

What are the solutions to the equation 4x^4-37x^2+9=0 ?
The solutions to the equation 4x^4-37x^2+9=0 are x=3,x=-3,x= 1/2 ,x=-1/2
Find the zeros of 4x^4-37x^2+9=0
The zeros of 4x^4-37x^2+9=0 are x=3,x=-3,x= 1/2 ,x=-1/2