What are the solutions to the equation x^3+x+2=0 ?

The solutions to the equation x^3+x+2=0 are x=-1,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2

Find the zeros of x^3+x+2=0

The zeros of x^3+x+2=0 are x=-1,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} + x + 2 = 0

x = - 1, x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

Solution steps

x^{3} + x + 2 = 0

Factor

x^{3} + x + 2 : (x + 1) (x^{2} - x + 2)

(x + 1) (x^{2} - x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x^{2} - x + 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x^{2} - x + 2 = 0 : x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

The solutions are

x = - 1, x = \frac{1}{2} + i \frac{7}{2}, x = \frac{1}{2} - i \frac{7}{2}

x^{4} = x^{2}

x^{3} + x^{2} + 1 = 0

x^{3} - 2 x^{2} = 0

x^{3} + x^{2} - 5 x + 3 = 0

y, y^{3} = C x^{4} - 3 x

What are the solutions to the equation x^3+x+2=0 ?
The solutions to the equation x^3+x+2=0 are x=-1,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2
Find the zeros of x^3+x+2=0
The zeros of x^3+x+2=0 are x=-1,x= 1/2+i(sqrt(7))/2 ,x= 1/2-i(sqrt(7))/2