What are the solutions to the equation 4x^3-8x^2-25x+50=0 ?

The solutions to the equation 4x^3-8x^2-25x+50=0 are x=2,x=-5/2 ,x= 5/2

Find the zeros of 4x^3-8x^2-25x+50=0

The zeros of 4x^3-8x^2-25x+50=0 are x=2,x=-5/2 ,x= 5/2

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4 x^{3} - 8 x^{2} - 25 x + 50 = 0

x = 2, x = - \frac{5}{2}, x = \frac{5}{2}

Decimal Notation

x = 2, x = - 2.5, x = 2.5

Solution steps

4 x^{3} - 8 x^{2} - 25 x + 50 = 0

Factor

4 x^{3} - 8 x^{2} - 25 x + 50 : (x - 2) (2 x + 5) (2 x - 5)

(x - 2) (2 x + 5) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x + 5 = 0 or 2 x - 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x + 5 = 0 : x = - \frac{5}{2}

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions are

x = 2, x = - \frac{5}{2}, x = \frac{5}{2}

n (n + 1) (2 n + 1) = 17220

5 x^{4} - 12 x^{3} = 0

x^{3} + 3 x^{2} + 2 x = 0

x^{4} - 12 x^{2} + 27 = 0

4 x^{4} - 17 x^{2} = - 18

What are the solutions to the equation 4x^3-8x^2-25x+50=0 ?
The solutions to the equation 4x^3-8x^2-25x+50=0 are x=2,x=-5/2 ,x= 5/2
Find the zeros of 4x^3-8x^2-25x+50=0
The zeros of 4x^3-8x^2-25x+50=0 are x=2,x=-5/2 ,x= 5/2