What are the solutions to the equation 3x(x-4)(3x+5)=0 ?

The solutions to the equation 3x(x-4)(3x+5)=0 are x=0,x=4,x=-5/3

Find the zeros of 3x(x-4)(3x+5)=0

The zeros of 3x(x-4)(3x+5)=0 are x=0,x=4,x=-5/3

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3 x (x - 4) (3 x + 5) = 0

x = 0, x = 4, x = - \frac{5}{3}

Decimal Notation

x = 0, x = 4, x = - 1.66666 \dots

Solution steps

3 x (x - 4) (3 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 4 = 0 or 3 x + 5 = 0

Solve

x - 4 = 0 : x = 4

Solve

3 x + 5 = 0 : x = - \frac{5}{3}

The solutions are

x = 0, x = 4, x = - \frac{5}{3}

66 = 8 \cdot m^{3}

x^{3} + 4 x^{2} - x - 4 = 0

x^{3} - 6 x^{2} + 21 x - 26 = 0

x^{2} = x^{3}

- x^{3} - 2 x^{2} + 4 x + 8 = 0

What are the solutions to the equation 3x(x-4)(3x+5)=0 ?
The solutions to the equation 3x(x-4)(3x+5)=0 are x=0,x=4,x=-5/3
Find the zeros of 3x(x-4)(3x+5)=0
The zeros of 3x(x-4)(3x+5)=0 are x=0,x=4,x=-5/3