What are the solutions to the equation p(p-3)^2-4(p-3)^3=0 ?

The solutions to the equation p(p-3)^2-4(p-3)^3=0 are p=3,p=4

Find the zeros of p(p-3)^2-4(p-3)^3=0

The zeros of p(p-3)^2-4(p-3)^3=0 are p=3,p=4

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p (p - 3)^{2} - 4 (p - 3)^{3} = 0

p = 3, p = 4

Solution steps

p (p - 3)^{2} - 4 (p - 3)^{3} = 0

Factor

p (p - 3)^{2} - 4 (p - 3)^{3} : - 3 (p - 3)^{2} (p - 4)

- 3 (p - 3)^{2} (p - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

p - 3 = 0 or p - 4 = 0

Solve

p - 3 = 0 : p = 3

Solve

p - 4 = 0 : p = 4

The solutions are

p = 3, p = 4

x^{3} - x^{2} - x = 0

2 x^{3} + 4 x^{2} - 9 = 0

x^{3} - x - 6 = 0

(x - 1) (x^{2} + 1) = - (x - 1)

x^{6} - 63 x^{3} - 64 = 0

What are the solutions to the equation p(p-3)^2-4(p-3)^3=0 ?
The solutions to the equation p(p-3)^2-4(p-3)^3=0 are p=3,p=4
Find the zeros of p(p-3)^2-4(p-3)^3=0
The zeros of p(p-3)^2-4(p-3)^3=0 are p=3,p=4