What are the solutions to the equation 5x^4-5=0 ?

The solutions to the equation 5x^4-5=0 are x=1,x=-1,x=i,x=-i

Find the zeros of 5x^4-5=0

The zeros of 5x^4-5=0 are x=1,x=-1,x=i,x=-i

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5 x^{4} - 5 = 0

x = 1, x = - 1, x = i, x = - i

Solution steps

5 x^{4} - 5 = 0

Move

5

to the right side

5 x^{4} = 5

Divide both sides by

5

x^{4} = 1

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} = 1

Solve

u^{2} = 1 : u = 1, u = - 1

u = 1, u = - 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 1 : x = 1, x = - 1

Solve

x^{2} = - 1 : x = i, x = - i

The solutions are

x = 1, x = - 1, x = i, x = - i

2 x^{3} - x^{2} - 8 x + 4 = 0

x^{3} - x + 2 = 0

x^{4} + x^{2} = 0

x^{3} - 12 x - 16 = 0

16 x^{4} - 48 x^{2} + 27 = 0

What are the solutions to the equation 5x^4-5=0 ?
The solutions to the equation 5x^4-5=0 are x=1,x=-1,x=i,x=-i
Find the zeros of 5x^4-5=0
The zeros of 5x^4-5=0 are x=1,x=-1,x=i,x=-i