What are the solutions to the equation 4x^3-12x^2+8x=0 ?

The solutions to the equation 4x^3-12x^2+8x=0 are x=0,x=1,x=2

Find the zeros of 4x^3-12x^2+8x=0

The zeros of 4x^3-12x^2+8x=0 are x=0,x=1,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{3} - 12 x^{2} + 8 x = 0

x = 0, x = 1, x = 2

Solution steps

4 x^{3} - 12 x^{2} + 8 x = 0

Factor

4 x^{3} - 12 x^{2} + 8 x : 4 x (x - 1) (x - 2)

4 x (x - 1) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x - 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 1, x = 2

x^{3} - 2 x^{2} = 4 x - 8

2 x^{4} - 15 x^{3} + 18 x^{2} = 0

x^{3} - 4 x^{2} + 4 x = 0

4 x^{4} + 10 x^{3} = 6 x^{2} + 15 x

r^{3} = 216

What are the solutions to the equation 4x^3-12x^2+8x=0 ?
The solutions to the equation 4x^3-12x^2+8x=0 are x=0,x=1,x=2
Find the zeros of 4x^3-12x^2+8x=0
The zeros of 4x^3-12x^2+8x=0 are x=0,x=1,x=2