What are the solutions to the equation 2x^3+3x^2=8x+12 ?

The solutions to the equation 2x^3+3x^2=8x+12 are x=-3/2 ,x=-2,x=2

Find the zeros of 2x^3+3x^2=8x+12

The zeros of 2x^3+3x^2=8x+12 are x=-3/2 ,x=-2,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{3} + 3 x^{2} = 8 x + 12

x = - \frac{3}{2}, x = - 2, x = 2

Decimal Notation

x = - 1.5, x = - 2, x = 2

Solution steps

2 x^{3} + 3 x^{2} = 8 x + 12

Move

12

to the left side

2 x^{3} + 3 x^{2} - 12 = 8 x

Move

8 x

to the left side

2 x^{3} + 3 x^{2} - 12 - 8 x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

2 x^{3} + 3 x^{2} - 8 x - 12 = 0

Factor

2 x^{3} + 3 x^{2} - 8 x - 12 : (2 x + 3) (x + 2) (x - 2)

(2 x + 3) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or x + 2 = 0 or x - 2 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{3}{2}, x = - 2, x = 2

x^{3} - 8 = x - 2

(3^{3})^{2} = n^{6}

(x - 1) (x^{2} - 2) = (x - 1) (x - 2)

2 x^{3} - 13 x^{2} + 36 = 0

x^{3} + 3 x^{2} - 10 x = 0

What are the solutions to the equation 2x^3+3x^2=8x+12 ?
The solutions to the equation 2x^3+3x^2=8x+12 are x=-3/2 ,x=-2,x=2
Find the zeros of 2x^3+3x^2=8x+12
The zeros of 2x^3+3x^2=8x+12 are x=-3/2 ,x=-2,x=2