What are the solutions to the equation x^3+ax^2-4x-4a=0 ?

The solutions to the equation x^3+ax^2-4x-4a=0 are x=-a,x=-2,x=2

Find the zeros of x^3+ax^2-4x-4a=0

The zeros of x^3+ax^2-4x-4a=0 are x=-a,x=-2,x=2

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x^{3} + a x^{2} - 4 x - 4 a = 0

x = - a, x = - 2, x = 2

Solution steps

x^{3} + a x^{2} - 4 x - 4 a = 0

Factor

x^{3} + a x^{2} - 4 x - 4 a : (x + a) (x + 2) (x - 2)

(x + a) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + a = 0 or x + 2 = 0 or x - 2 = 0

Solve

x + a = 0 : x = - a

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - a, x = - 2, x = 2

3 x^{5} = 24 x

4 x^{3} - 64 x = 0

x^{3} + 2 x^{2} - 3 x = 0

z^{6} + 8 = 0

- 4 x^{3} + 5 x^{2} + 2 x - 2 = 0

What are the solutions to the equation x^3+ax^2-4x-4a=0 ?
The solutions to the equation x^3+ax^2-4x-4a=0 are x=-a,x=-2,x=2
Find the zeros of x^3+ax^2-4x-4a=0
The zeros of x^3+ax^2-4x-4a=0 are x=-a,x=-2,x=2