What are the solutions to the equation 4=x^3-x^2+x-2 ?

The solutions to the equation 4=x^3-x^2+x-2 are x=2,x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

Find the zeros of 4=x^3-x^2+x-2

The zeros of 4=x^3-x^2+x-2 are x=2,x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2

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4 = x^{3} - x^{2} + x - 2

x = 2, x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

Solution steps

4 = x^{3} - x^{2} + x - 2

Switch sides

x^{3} - x^{2} + x - 2 = 4

Move

4

to the left side

x^{3} - x^{2} + x - 6 = 0

Factor

x^{3} - x^{2} + x - 6 : (x - 2) (x^{2} + x + 3)

(x - 2) (x^{2} + x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + x + 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + x + 3 = 0 : x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

The solutions are

x = 2, x = - \frac{1}{2} + i \frac{11}{2}, x = - \frac{1}{2} - i \frac{11}{2}

x^{5} = - 1

x, x^{3} = y^{3}

x^{8} - 16 = 15 x^{4}

x^{3} = 25

x^{4} - 4 x^{2} + 2 = 0

What are the solutions to the equation 4=x^3-x^2+x-2 ?
The solutions to the equation 4=x^3-x^2+x-2 are x=2,x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2
Find the zeros of 4=x^3-x^2+x-2
The zeros of 4=x^3-x^2+x-2 are x=2,x=-1/2+i(sqrt(11))/2 ,x=-1/2-i(sqrt(11))/2